IP Adress dan subneting

Menghitung IP Adress sebagai berikut :

1. 10.10.10.1/27
2. 192.168.100.1/28
3. 172.16.33.1/25
4. 40.40.40.2/29
5. 55.55.55.55/27
6. 12.12.12.12/28
7. 200.168.10.1/30

berikut ini penjelasan dalam menghitung IP Adress dan subneting....

1. 10.10.10.1/27

• Subnet Max : 255.255.255.224
• Jumlah Host : 2ⁿ- 2 = 2⁵- 2        

        = 32 - 2
        = 30 

• Jumlah Network : 2ⁿ = 2³ = 8
• Blok Persubnet : 256 - 224 = 32

(0,32,64,96,128,160,192,224)

2. 192.168.100.1/28

• Subnet Mask : 255.255.255.240
• Jumlah host persubnet :

          2ⁿ -2 = 2⁴-2
          = 16-2
          = 14

•  Blok Persubnet = 256 - 240 = 16

( 0,16,32,48,64,80,96,112,128,144,160,176,192,208,224,240 )

3. 172.16.33.1/25

• Subnet Mask : 255.255.255.128
• Jumlah Host Persubnet :

          2ⁿ -2 = 2⁷-2

= 128-2 

= 126

•  Jumlah Network : 2ⁿ = 2¹ 

                                              = 2 

• Jumlah Blok Persubnet = 256-128 = 128

( 0,128 )

4. 40.40.40.2/29

• Subnet Mask : 255.255.255.248
• Jumlah Host Persubnet :

               2ⁿ -2 = 2³-2

                        = 8-2

                        = 6

• Jumlah Network : 2ⁿ = 2⁵ 

                                                ^:32

• Blok Persubnet = 256 - 248 = 8

^{(0,8,16,24,32,40,48,56,64,72,80,88,96,104,112,120,128,136,144,152,160,168,176,184,192,200,208,216,224,232,240,248)}

^{5. 55.55.55.55/27}

• Subnet Mask : 255.255.255.224
• Jumlah Host Persubnet :

                2ⁿ-2 = 2⁵-2

                        = 32-2

                        = 30 

• Jumlah Network : 2ⁿ = 2³ = 8
• Blok Persubnet = 256 - 224 = 32

(0,32,64,96,128,160,192,224)

6. 12.12.12.12/28

• Subnet Mask : 255.255.255.240
• Jumlah Host Persubnet :

                2ⁿ -2 = 2⁴-2

                         = 16-2

                         = 14

• Blok Persubnet = 256 - 240 = 16

(0,16,32,48,64,80,96,112,144,160,176,192,208,224,240)

7. 200.168.10.1/30

• Subnet Mask : 255.255.255.252
• Jumlah Host Persubnet : 

              2ⁿ -2 = 2²- 2

                         = 4 - 2

                         =2

• Jumlah Network = 2ⁿ 

                          = 2⁶

                          = 64

• Blok Persubnet = 256 - 252 =4

(0,4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80,84,88,92,,96,100,104,108,112,116,120,124,128,132,136,140,144,148,152,156,160,164,168,172,176,180,184,188,192,196,200,204,208,212,216,220,224,228,232,236,240,244,248,252)

REFERENSI : 

Tugas Belajar Praktikum P04

Firlandhi Julfian Syariffudin-13180953